
Position 15 has the word FizzBuzz because it is a multiple of both 3 and 5. Positions 5 and 10 have the word "Buzz" because they are multiples of 5. Position 3,6,9,12 have the word "Fizz" because they are multiples of 3. For numbers which are multiples of both three and five print “FizzBuzz”. But for multiples of three print “Fizz” instead of the number 3 and for the multiples of five print “Buzz”.
If none of the above conditions match, then print i.Write a program which prints the numbers from 1 to N, each on a new line. Similarly, if the value of count5 is equal to 5, print “Buzz” and set count5 = 0. If the value of count3 is equal to 3, print “Fizz” and set count3 = 0. Iterate over the range using a variable, say i, and perform the following steps:. Initialize two count variables, say count3 and count5, to store the count of numbers divisible by 3 and 5 respectively. But for large integers, it is observed that the runtime is much slower in the modulo operation program than the other, with O(N 2) computational complexity.įollow the below steps to solve the problem:. However, modern CPUs use specialized division circuits with lookup tables and so, there won’t be any significant change in speed by using bit-shifting. The DIV instruction of the compiler gives the division and modulo results. In the lowest level, modulo is a division. Modulo operator is a very expensive operation.
Refer to the previous post of this article for this approach.Īpproach without using modulo operator : The above problem can be solved without using the modulo operator because: Recommended: Please try your approach on first, before moving on to the solution.Īpproach using modulo operator : The simplest approach to solve this problem is to use modulo operator.
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The object of the assignment is less about solving it correctly according to the below rules and more about showing the programmer understands basic, necessary tools such as if -/ else -statements and loops. Data Structure & Algorithm Classes (Live) FizzBuzz is a game that has gained in popularity as a programming assignment to weed out non-programmers during job interviews.